What inspired me to start this was an incident last night going over my son's calculus homework.It was a relatively simple integral, as integrals go:
∫ x (x +2) dx / (x3 + 3x2 -4)
The answer is to sort of work backwards, since the derivative is easy, after setting the right value for u
1/3 ∫ (3x2 +6x) dx / (x3 + 3x2 -4) where u = x3 + 3x2 -4 and therefore du /dx = 3x2 +6x
this simplifies the equation to 1/3 ∫ du / u = 1/3 ln | u | + c
then substituting back again we get the final answer 1/3 ln | x3 + 3x2 -4 | + c
No big deal, but really all I did was simplify the equation to a form where I knew the derivative to the values in the integral. Derivatives are easy, integrals are hard.
I hope to use this blog to help simplify computing issues to simple doable ones. Just for fun here is a video on substitution for integral calculus